Gathering Pokémon without a loop

A list containing 720 Pokémon has been loaded into your session as poke_names. Another list containing each Pokémon's corresponding generation has been loaded as poke_gens.

A for loop has been created to filter the Pokémon that belong to generation one or two, and collect the number of letters in each Pokémon's name:

gen1_gen2_name_lengths_loop = []

for name,gen in zip(poke_names, poke_gens):
    if gen < 3:
        name_length = len(name)
        poke_tuple = (name, name_length)
        gen1_gen2_name_lengths_loop.append(poke_tuple)

Questo esercizio fa parte del corso

Writing Efficient Python Code

Visualizza il corso

Istruzioni dell'esercizio

Eliminate the above for loop using list comprehension and the map() function:
- Use list comprehension to collect each Pokémon that belongs to generation 1 or generation 2. Save this as gen1_gen2_pokemon.
- Use the map() function to collect the number of letters in each Pokémon's name within the gen1_gen2_pokemon list. Save this map object as name_lengths_map.
- Combine gen1_gen2_pokemon and name_lengths_map into a list called gen1_gen2_name_lengths.

Esercizio pratico interattivo

Prova a risolvere questo esercizio completando il codice di esempio.

# Collect Pokémon that belong to generation 1 or generation 2
gen1_gen2_pokemon = [name for name,gen in ____(____, ____) if gen < ____]

# Create a map object that stores the name lengths
name_lengths_map = ____(len, ____)

# Combine gen1_gen2_pokemon and name_lengths_map into a list
gen1_gen2_name_lengths = [*____(____, ____)]

print(gen1_gen2_name_lengths_loop[:5])
print(gen1_gen2_name_lengths[:5])

Modifica ed esegui il codice