vapply() vs. sapply()
In the last example, sapply()
failed to simplify because the date
element of market_crash2
had two classes (POSIXct and POSIXt). Notice, however, that no error was thrown! If a function you had written expected a simplified vector to be returned by sapply()
, this would be confusing.
To account for this, there is a more strict apply function called vapply()
, which contains an extra argument FUN.VALUE
where you can specify the type and length of the output that should be returned each time your applied function is called.
If you expected the return value of class()
to be a character vector of length 1, you can specify that using vapply()
:
vapply(market_crash, class, FUN.VALUE = character(1))
dow_jones_drop date
"numeric" "Date"
Other examples of FUN.VALUE
might be numeric(2)
or logical(1)
. market_crash2
is again defined for you.
Este ejercicio forma parte del curso
Intermediate R for Finance
Instrucciones del ejercicio
- Use
sapply()
again to find theclass()
ofmarket_crash2
elements. Notice how it returns a list and not an error. - Use
vapply()
onmarket_crash2
to find theclass()
. SpecifyFUN.VALUE = character(1)
. It should appropriately fail.
Ejercicio interactivo práctico
Prueba este ejercicio y completa el código de muestra.
# Market crash with as.POSIXct()
market_crash2 <- list(dow_jones_drop = 777.68,
date = as.POSIXct("2008-09-28"))
# Find the classes with sapply()
___
# Find the classes with vapply()
___