Keyword arguments of variable size
Now let's move to keyword arguments of variable size! Your task is to define the function key_types(). It should take a variable number of keyword arguments and return a new dictionary: the keys are unique object types of arguments passed to the key_types() function and the associated values represent lists. Each list should contain argument names that follow the type defined as a key (e.g. calling the key_types(kwarg1='a', kwarg2='b', kwarg3=1) results in {<class 'int'>: ['kwarg3'], <class 'str'>: ['kwarg1', 'kwarg2']}).
To retrieve the type of an object, you need to use the type() function (e.g. type(1) is int).
Bu egzersiz, kursun bir parçasıdır
Practicing Coding Interview Questions in Python
Egzersiz talimatları
- Define the function with an arbitrary number of keyword arguments.
- Iterate over key-value pairs.
- Update a list associated with a key.
Uygulamalı etkileşimli egzersiz
Bu egzersizi bu örnek kodu tamamlayarak deneyin.
# Define the function with an arbitrary number of arguments
def key_types(____):
dict_type = dict()
# Iterate over key value pairs
for key, value in kwargs.____:
# Update a list associated with a key
if ____(____) in ____:
dict_type[____].____
else:
dict_type[____] = [____]
return dict_type
res = key_types(a=1, b=2, c=(1, 2), d=3.1, e=4.2)
print(res)