按班次划分的上车地点

现在来解决该业务案例的第二个目标。在每个 NYC Borough 内，各上车地点与各班次的 AvgFarePerKM、RideCount 和 TotalRideMin 分别是多少？

本练习是课程的一部分

SQL Server 中的函数与存储过程编写

练习说明

创建名为 cuspPickupZoneShiftStats 的存储过程，接收 @Borough nvarchar(30) 作为输入参数，并仅返回 Borough 值匹配的记录。
计算 'Shift'：将 PickupDate 的 hour 传入 dbo.GetShiftNumber() 函数。使用 DATEPART 仅选取 PickupDate 的 hour 部分。
按 PickupDate 的工作日、班次和 Zone 分组。
按 PickupDate 的工作日（周一在前）、班次以及 TotalRideMin 排序。

交互式实操练习

通过完成这段示例代码来试试这个练习。

-- Create the stored procedure
CREATE PROCEDURE dbo.cuspPickupZoneShiftStats
	-- Specify @Borough parameter
	@Borough nvarchar(30)
AS
BEGIN
SELECT
	DATENAME(WEEKDAY, PickupDate) as 'Weekday',
    -- Calculate the shift number
	___.___(___(___, ___)) as 'Shift',
	Zone.Zone as 'Zone',
	FORMAT(AVG(dbo.ConvertDollar(TotalAmount, .77)/dbo.ConvertMiletoKM(TripDistance)), 'c', 'de-de') AS 'AvgFarePerKM',
	FORMAT(COUNT (ID),'n', 'de-de') as 'RideCount',
	FORMAT(SUM(DATEDIFF(SECOND, PickupDate, DropOffDate))/60, 'n', 'de-de') as 'TotalRideMin'
FROM YellowTripData
INNER JOIN TaxiZoneLookup as Zone on PULocationID = Zone.LocationID 
WHERE
	dbo.ConvertMiletoKM(TripDistance) > 0 AND
	Zone.Borough = @Borough
GROUP BY
	DATENAME(WEEKDAY, PickupDate),
    -- Group by shift
	___.___(___(___, ___)),  
	Zone.Zone
ORDER BY CASE WHEN DATENAME(WEEKDAY, PickupDate) = 'Monday' THEN 1
              WHEN DATENAME(WEEKDAY, PickupDate) = 'Tuesday' THEN 2
              WHEN DATENAME(WEEKDAY, PickupDate) = 'Wednesday' THEN 3
              WHEN DATENAME(WEEKDAY, PickupDate) = 'Thursday' THEN 4
              WHEN DATENAME(WEEKDAY, PickupDate) = 'Friday' THEN 5
              WHEN DATENAME(WEEKDAY, PickupDate) = 'Saturday' THEN 6
              WHEN DATENAME(WEEKDAY, PickupDate) = 'Sunday' THEN 7 END,
         -- Order by shift
         ___.___(___(___, ___)),
         SUM(DATEDIFF(SECOND, PickupDate, DropOffDate))/60 DESC
END;

编辑并运行代码