Exception object
It is not unusual for a piece of code to throw a number of exceptions. One way to handle this situation is to try-catch all exceptions and then use the exception object to determine what issue has happened and to output information from the Exception to debug the problem.
Here, you will modify the SplitTheBill application again to catch a generic Exception and use data from the Exception object to understand the cause of the problem. Exception objects contain a lot of useful information, including a trace of methods leading to the problem.
Bu egzersiz
Data Types and Exceptions in Java
kursunun bir parçasıdırEgzersiz talimatları
- In the catch block, capture any
Exceptionusingcatch (Exception e). - Use the
Exceptionand object reference (e) and thegetClass()method in thecatchblock to display the type (class) of exception caught. - Use the
Exceptionobject reference (e) and thegetMessage()method to print the exception's message. - Print the "stack trace" to the output stream using the
Exceptionobject reference (e) and theprintStackTrace()method.
Uygulamalı interaktif egzersiz
Bu örnek kodu tamamlayarak bu egzersizi bitirin.
class SplitTheBill {
public static void main(String[] args) {
BigDecimal bill = new BigDecimal(125.50);
computeEachBill(bill, 5);
computeEachBill(bill, 0);
}
public static void computeEachBill(BigDecimal bill, int people) {
try {
BigDecimal numPeople = new BigDecimal(people);
BigDecimal individualBill = bill.divide(numPeople);
System.out.println("Bill for each person is: " + individualBill);
// Catch any exception
} catch (____ ____) {
System.out.println("You didn't provide a positive number of people to split the bill among.");
// Print the type (class) of exception
System.out.println("Type of exception: " + ____.____());
// Print the exception message
System.out.println(____.____());
// Print the stack trace
____.____();
}
}
}