Aggregating finances
In this exercise you would like to learn more about the differences in payments between the customers who are active and those who are not.
Questo esercizio fa parte del corso
Applying SQL to Real-World Problems
Istruzioni dell'esercizio
- Find out the differences in their total number of payments by
COUNT()ing thepayment_id. - Find out the differences in their average payments by using
AVG(). - Find out the differences in their total payments by using
SUM(). - Ensure the aggregate functions
GROUP BYwhether customer payments areactive.
Esercizio pratico interattivo
Prova a risolvere questo esercizio completando il codice di esempio.
SELECT active,
___ AS num_transactions,
___ AS avg_amount,
___ AS total_amount
FROM payment AS p
INNER JOIN customer AS c
ON p.customer_id = c.customer_id
GROUP BY ___;