Comparing search algorithm performance
As a software developer at an e-commerce company, you're evaluating different search methods to improve product search functionality. Until now, the search mechanism the company was using was very slow, but you managed to remove that delay already. Your task now is to compare your new search method with the old one, to prove it is more efficient for your catalog search feature.
Este ejercicio forma parte del curso
Optimizing Code in Java
Instrucciones del ejercicio
- Find the target element using the new search method,
linearSearch(). - Then, find the target element using the old search method,
linearSearchWithDelay(). - Calculate the relative performance difference of the search methods.
Ejercicio interactivo práctico
Prueba este ejercicio y completa el código de muestra.
public class SearchPerformanceTest {
public static void main(String[] args) {
int[] array = new int[10000];
for (int i = 0; i < array.length; i++) {
array[i] = i;
}
int target = array[7500]; // Target value to search for
long startRegular = System.nanoTime();
// Do a search using the new search method
boolean foundRegular = ____(array, target);
long endRegular = System.nanoTime();
long startDelay = System.nanoTime();
// Do a search using the old search method
boolean foundDelay = ____(array, target);
long endDelay = System.nanoTime();
// Calculate the ratio between the old and new methods
double ratio = (double)(endDelay - startDelay) / (____ - ____);
System.out.println("Linear search with delay is " + ratio +
" times slower than regular linear search");
}
private static boolean linearSearch(int[] data, int target) {
for (int i = 0; i < data.length; i++) {
if (data[i] == target) return true;
}
return false;
}
private static boolean linearSearchWithDelay(int[] data, int target) {
for (int i = 0; i < data.length; i++) {
try {
Thread.sleep(0, 1000); // 1000 nanoseconds delay
} catch (InterruptedException e) {
e.printStackTrace();
}
if (data[i] == target) return true;
}
return false;
}
}