The keyword nonlocal and nested functions

Let's once again work further on your mastery of scope! In this exercise, you will use the keyword nonlocal within a nested function to alter the value of a variable defined in the enclosing scope.

This exercise is part of the course

Introduction to Functions in Python

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Exercise instructions

Assign to echo_word the string word, concatenated with itself.
Use the keyword nonlocal to alter the value of echo_word in the enclosing scope.
Alter echo_word to echo_word concatenated with '!!!'.
Call the function echo_shout(), passing it a single argument 'hello'.

Hands-on interactive exercise

Have a go at this exercise by completing this sample code.

# Define echo_shout()
def echo_shout(word):
    """Change the value of a nonlocal variable"""
    
    # Concatenate word with itself: echo_word
    ____
    
    # Print echo_word
    print(echo_word)
    
    # Define inner function shout()
    def shout():
        """Alter a variable in the enclosing scope"""    
        # Use echo_word in nonlocal scope
        ____
        
        # Change echo_word to echo_word concatenated with '!!!'
        echo_word = ____
    
    # Call function shout()
    shout()
    
    # Print echo_word
    print(echo_word)

# Call function echo_shout() with argument 'hello'
____

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