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Create a list-column data.frame

Let's end our chapter with an implementation of our links extractor, but using a list-column. The idea when using a nested dataframe (i.e., dataframe with a list column) is to keep everything inside a dataframe so that the workflow stays tidy.

You have been provided a tibble called df, which has a column urls with the four URLs you've been using since the beginning of this chapter. If you want to have a look at this dataframe, feel free to print it in the console.

We are going to create a new column called links, which contains the results of the get_links() function (available in your workspace). As the outputs of this function have different lengths, the output will be a list column that you will then need to unnest() to get back a standard dataframe.

This exercise is part of the course

Intermediate Functional Programming with purrr

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Exercise instructions

  • Load the three necessary packages: dplyr, tidyr, and purrr

  • Take the df element, and run mutate() on it. mutate() will map the get_links() function on the urls column.

  • Print the result.

  • Unnest the result.

Hands-on interactive exercise

Have a go at this exercise by completing this sample code.

# Load dplyr, tidyr, and purrr




# Create a "links" columns, by mapping get_links() on urls
df2 <- df %>%
  mutate(___ = map(___, get_links)) 

# Print df2 to see what it looks like


# unnest() df2 to have a tidy dataframe
df2 %>%
  ___(cols=c(links))
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