Comparing two proportions (2)

Now we have calculated the pooled estimate $\hat{p}$, we can move on to calculate the standard error. The formula for the standard error is the following:

$$se = \sqrt{\hat{p} * (1 - \hat{p}) * (\frac{1}{n1} + \frac{1}{n2})}$$

This exercise is part of the course

Inferential Statistics

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Exercise instructions

The pooled estimate is given in the sample code. It is named pooled. Use this variable to calculate the standard error and store this in the variable called se. Remeber that the sample sizes n1 = 100 and n2 = 150

Hands-on interactive exercise

Have a go at this exercise by completing this sample code.

# calculate the difference in sample proportions and store it in a variable called difference
difference <- 0.6 - 0.42


# calculate the pooled estimate and store it in a variable called pooled
pooled <- ((0.6 * 100) + (0.42 * 150)) / (100 + 150)

# calculate the standard error and store it in a variable called se

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